m3rk098 m3rk098
  • 01-05-2018
  • Mathematics
contestada

hey can you please help me posted picture of question

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11beehshahbaz 11beehshahbaz
  • 01-05-2018
The solutions to the given quadratic equation can be determined using quadratic formula.

[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]

b =coefficient of x term = -3
a = coefficient of squared term = 1
c = constant term = 3

Using the values in the above formula we get:

[tex]x= \frac{3+- \sqrt{9-4(1)(3)} }{2(1)} \\ \\ x= \frac{3+- \sqrt{-3} }{2} \\ \\ x= \frac{3+- \sqrt{3}i }{2} [/tex]

Thus, option A gives the correct solution
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