marlisamoore
marlisamoore
01-09-2017
Mathematics
contestada
can someone help me with this question
Respuesta :
Banabanana
Banabanana
01-09-2017
[tex] x^{2} +2x-5=0 \\ D=b^2-4ac=2^2-4*1*(-5)=4+20=24 \\ x_{1,2}= \frac{-bб \sqrt{D} }{2a}= \frac{-2б \sqrt{24} }{2}=\frac{-2б 2\sqrt{6} }{2}= \frac{-2}{2}б \frac{2 \sqrt{6} }{2} =-1б \sqrt{6} [/tex]
Answer:
B. x = -1 - √6
C. x = -1 + √6
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