Explanation:
Question: According to the reaction N2 + 3 H->2NH3, we can say that 1 gram of N2 reacts with 3 grams of H2 to produce 2 grams of NH3.
First, we need to find the value in moles of 1 gram of N2 and 3 grams of H2. For this, we use the following equation: n = m/MM
MM of N2 = 28 g/mol
MM oh H2 = 2 g/mol
n of N2 = 1/28 = 0.04 moles of N2
n of H2 = 3 moles of H2
It is false, because the reaction tells us that 1 mole of N2 will react with 3 moles of H2, producing 2 moles of NH3.
Answer: False
