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) It is necessary to maintain a constant fluid volume in the body. Therefore, the body adjusts the water outputs to be equal to the inputs. So, if an animal consumes 1.0 kg of water in feed and 5.0 kg of drinking water, produces 0.5 kg of metabolic water in the body, and excretes a total of 4.5 kg of water in feces and urine, calculate the amount (kg) of evaporative water losses of this animal (show your work).

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Answer:

Evaporative Water Loss = 2 kg

Explanation:

According to the given condition, the water entering the body must be equal to the water leaving the body. Therefore,

Water Entering the Body = Water Leaving the Body

Feed Water + Drinking Water + Metabolic Water = Urine Water + Evaporative Water Loss

using the given values:

1 kg + 5 kg + 0.5 kg = 4.5 kg + Evaporative Water Loss

Evaporative Water Loss = 1 kg + 5 kg + 0.5 kg - 4.5 kg

Evaporative Water Loss = 2 kg

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