subedia341 subedia341
  • 01-11-2020
  • Mathematics
contestada

prove that 1-tan32°tan13°-tan32°-tan13°=0​

Respuesta :

surjithayer10 surjithayer10
  • 01-11-2020

Answer:

Step-by-step explanation:

45=32+13

tan 45=tan(32+13)

[tex]1=\frac{tan~ 32+tan~ 13}{1-tan ~32 ~tan~ 13} \\cross~multiply \\1-tan 32 ~tan~13=tan ~32+tan~13\\[/tex]

or  1-tan 32 tan 13-tan 32-tan 13=0

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