Answer:
chicken potato beans  chicken rice beans  chicken potato broccoli  chicken rice broccoli  salmon potato beans  salmon rice beans  salmon potato broccoli  salmon rice broccoli  steak potato beans  steak rice beans  steak potato broccoli  steak rice broccoli
Step-by-step explanation:
use the chart but do chicken etc..
The probability of a guest requesting either potatoes or beans if the guest chooses at random is 14/35 or 0.4.c
It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
Sophie asks each dinner guest to select one choice from each list:main (chicken, salmon, or steak), side (potato or rice), and vegetable (beans or broccoli).
The list can be made:
Sample space = {(chicken, potato, beans), (chicken, potato, broccoli) and so on}
Total items = 3+2+2 = 7
Number of ways = C(7, 3) = 35
Number of ways for potatoes = C(7, 1) = 7
Number of ways for beans = C(7, 1) = 7
The probability of a guest requesting either potatoes or beans if the guest chooses at random is:
= 7/35 + 7/35
= 14/35
= 0.4
Thus, the probability of a guest requesting either potatoes or beans if the guest chooses at random is 14/35 or 0.4.
Learn more about the probability here:
brainly.com/question/11234923
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