04-09-2014
Mathematics

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3ax-n/5=-4 solve for x

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04-09-2014

[tex]3ax-\frac{n}{5}=-4\ \ \ |Add\ \frac{n}{5}\ to\ both\ sides\\\\ 3ax=-4+\frac{n}{5}\\\\ 3ax=-\frac{20}{5}+\frac{n}{5}\\\\ 3ax=\frac{-20+n}{5}\ \ \ |Divide\ by\ 3a\\\\ x=\frac{-20+n}{5}*\frac{1}{3a}\\\\ x=\frac{-20+n}{15a}\\\\Asnwer\ is\ x=\frac{-20+n}{15a}.[/tex]

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